The no of possible ordered binary trees with 5 nodes A, B, C, D, E is
a. 15 b. 9 c. 41 d. 42
The answer is d. 42
The number of possible ordered binary trees is given by the formula :
1/n+1 (2n C n)
1/n+1 (2n C n)
Here n is 5, 1/n+1 (2n C n) = 1/6 (10 C 5) = 42.
The formula 1/n+1 (2n C n) is bit more complex. The derivation of the formula we shall discuss in one of the future posts.
Note: nCr = n! / (r! * (n-r)!)
The formula 1/n+1 (2n C n) is bit more complex. The derivation of the formula we shall discuss in one of the future posts.
Note: nCr = n! / (r! * (n-r)!)
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