A Binary Search tree is generated by inserting in order the following integers: 50, 12, 62, 5, 20, 58, 91, 3, 8, 37, 60, 24. The number of nodes in the left subtree and right subtree of the root respectively is

a) (4, 7) b) (7,4) c) (8,3) d) (3,8)

Binary search tree(BST), is also called an ordered tree or sorted binary tree, is a node-based binary tree data structure which has the following properties:

The left subtree of a node contains only nodes with keys less than the node's key.

The right subtree of a node contains only nodes with keys greater than the node's key.

The left and right subtree must each also be a binary search tree and their must be no duplicate nodes.

Suppose x is a node in a binary search tree and y is another node in the left subtree of x, then y.key < x.key. If y is a node in the right subtree of y then x.key < y.key.

Insertion begins as a search would begin; if the key is not equal to that of the root, we search the left or right subtrees. Eventually, we will reach a null pointer and add the new node to the leaf node (trailing pointer) as its right or left child, depending on the leaf node's key.

Binary search tree(BST), is also called an ordered tree or sorted binary tree, is a node-based binary tree data structure which has the following properties:

The left subtree of a node contains only nodes with keys less than the node's key.

The right subtree of a node contains only nodes with keys greater than the node's key.

The left and right subtree must each also be a binary search tree and their must be no duplicate nodes.

Suppose x is a node in a binary search tree and y is another node in the left subtree of x, then y.key < x.key. If y is a node in the right subtree of y then x.key < y.key.

Insertion begins as a search would begin; if the key is not equal to that of the root, we search the left or right subtrees. Eventually, we will reach a null pointer and add the new node to the leaf node (trailing pointer) as its right or left child, depending on the leaf node's key.

Let us insert the elements into a binary search tree in sequence 50, 12, 62, 5, 20, 58, 91, 3, 8, 37, 60, 24.

Algorithm: Tree-Insert(T, z)

{

// Algorithm to insert z in T, where x, y, z are nodes

// and x.key is the value of node x, x.right is the right pointer of x

y = NULL;

x = T.root;

//Searches x in T

while(x != NULL)

{

y = x; //y is the trailing pointer

if(z.key < x.key)

x = x.left;

else

x = x.right;

}

// z is added to the trailing pointer depending on y's value

if (y == NULL)

Algorithm: Tree-Insert(T, z)

{

// Algorithm to insert z in T, where x, y, z are nodes

// and x.key is the value of node x, x.right is the right pointer of x

y = NULL;

x = T.root;

//Searches x in T

while(x != NULL)

{

y = x; //y is the trailing pointer

if(z.key < x.key)

x = x.left;

else

x = x.right;

}

// z is added to the trailing pointer depending on y's value

if (y == NULL)

T.root = z; //Tree T was empty

else if(z.key < y.key)

y.left = z;

else

y.right = z;

}

Running time: O(h) , where h is the height of the tree.else if(z.key < y.key)

y.left = z;

else

y.right = z;

}

When we look at the final tree that has been generated, the answer will be b) (7, 4).

Just looking at the sequence 50, 12, 62, 5, 20, 58, 91, 3, 8, 37, 60, 24, we know that 50 is inserted as the root node, the elements less than 50 would go into the left subtree of 50 and the elements more than 50 would go into the right subtree of 50. All that we have to do is count the integers less than 50 and the integers more than 50.

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